已知XY=5,(X-Y)²=16,求:(1)X²+Y² (2)X+
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已知XY=5,(X-Y)²=16,求:(1)X²+Y² (2)X+Y
![已知XY=5,(X-Y)²=16,求:(1)X²+Y² (2)X+](/uploads/image/z/18094804-52-4.jpg?t=%E5%B7%B2%E7%9F%A5XY%3D5%2C%28X-Y%29%26%23178%3B%3D16%2C%E6%B1%82%EF%BC%9A%EF%BC%881%EF%BC%89X%26%23178%3B%2BY%26%23178%3B%26%23160%3B%26%23160%3B+%282%29X%2B)
x^2+y^2=(x-y)²+2xy=16+10=26
(x+y)^2=(x-y)²+4xy=16+20=36
所以x+y=6,-6
(x+y)^2=(x-y)²+4xy=16+20=36
所以x+y=6,-6
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