已知cos θ=1/3,θ∈(0,π),则cos(3π/2+2θ)
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已知cos θ=1/3,θ∈(0,π),则cos(3π/2+2θ)
![已知cos θ=1/3,θ∈(0,π),则cos(3π/2+2θ)](/uploads/image/z/18074783-47-3.jpg?t=%E5%B7%B2%E7%9F%A5cos+%CE%B8%3D1%2F3%2C%CE%B8%E2%88%88%280%2C%CF%80%29%2C%E5%88%99cos%283%CF%80%2F2%2B2%CE%B8%29)
cos(3π/2+2θ)=sin(2θ)=2*sin(θ)*cos(θ), 再根据sin(θ)^2+ cos(θ)^2 = 1(cos此处取正值), 即可求出答案,自己算一算吧,很简单
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