3^(1+log3 6)+10^(3lg 3)+1/9^(log3 4)
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3^(1+log3 6)+10^(3lg 3)+1/9^(log3 4)
RT
RT
![3^(1+log3 6)+10^(3lg 3)+1/9^(log3 4)](/uploads/image/z/17977090-58-0.jpg?t=3%5E%281%2Blog3+6%29%2B10%5E%283lg+3%29%2B1%2F9%5E%28log3+4%29)
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=45又16分之1
计算log3[(9^2 * 27^(1/3))/3^(log3 234)]
解方程log3 (9^x+8) = x+log3 (3^x+1 + 6)
解不等式:log3^(5+x)+log3^(x-1)≤3
(log3 4+log3 8)(log2 3+log2 9)+(log3 根号2)(log9 7)/(log1/3 7)
Log3(9^2*27^(1/3))=?
计算:lg(1/2)-lg(5/8)+lg(12.5)+log2为底3*log3为底8=
计算log2 6-log2 3,lg5+lg2,log5 3+log5 1/3,log3 5-log3 15
求函数y=log3 (3x)*log3 (x/9) (1/3
(log2^3 +log3^5) x ( log3^5 +log9^5 ) x lg 2 ,
log2(3)+log3(5)+log3(2)=?
为什么1/log5(3)等于log3(5) ?
Y=(log3 3x/x+1) 2的乘方 — log3 9(x+1)/x X log3 (x+1)2的乘方/9x 2的乘