用高斯消元法解下列现行方程组x1+2x2-x3=2 2x1+3x2+x3=11 x1-x2+2x3=5 x1+x2+x3
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用高斯消元法解下列现行方程组x1+2x2-x3=2 2x1+3x2+x3=11 x1-x2+2x3=5 x1+x2+x3=6
![用高斯消元法解下列现行方程组x1+2x2-x3=2 2x1+3x2+x3=11 x1-x2+2x3=5 x1+x2+x3](/uploads/image/z/17951438-38-8.jpg?t=%E7%94%A8%E9%AB%98%E6%96%AF%E6%B6%88%E5%85%83%E6%B3%95%E8%A7%A3%E4%B8%8B%E5%88%97%E7%8E%B0%E8%A1%8C%E6%96%B9%E7%A8%8B%E7%BB%84x1%2B2x2-x3%3D2+2x1%2B3x2%2Bx3%3D11+x1-x2%2B2x3%3D5+x1%2Bx2%2Bx3)
x1,2,2=x,y,z
x+2y-z=2
2x+3y+z=11
x-y+2z=5
x+y+z=6
x+2y-z=2
0+1/2y-3/2z=-7/2 ==> 0+y-3z=-7
0+3y-3z=-3 ==> 0+y-z=-1
0+y-2z=-4
x+2y-z=2
0+y-3z=-7
0+0+z=3(3式-4式,4式-2式)
x+0+0=1
0+y+0=2
0+0+z=3
x=1,y=2,z=3
x+2y-z=2
2x+3y+z=11
x-y+2z=5
x+y+z=6
x+2y-z=2
0+1/2y-3/2z=-7/2 ==> 0+y-3z=-7
0+3y-3z=-3 ==> 0+y-z=-1
0+y-2z=-4
x+2y-z=2
0+y-3z=-7
0+0+z=3(3式-4式,4式-2式)
x+0+0=1
0+y+0=2
0+0+z=3
x=1,y=2,z=3
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