若等比数列{an}的前n项和为Sn=32n+1+t,则公比q等于______,t=______.
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若等比数列{an}的前n项和为Sn=32n+1+t,则公比q等于______,t=______.
![若等比数列{an}的前n项和为Sn=32n+1+t,则公比q等于______,t=______.](/uploads/image/z/17928242-26-2.jpg?t=%E8%8B%A5%E7%AD%89%E6%AF%94%E6%95%B0%E5%88%97%7Ban%7D%E7%9A%84%E5%89%8Dn%E9%A1%B9%E5%92%8C%E4%B8%BASn%3D32n%2B1%2Bt%EF%BC%8C%E5%88%99%E5%85%AC%E6%AF%94q%E7%AD%89%E4%BA%8E______%EF%BC%8Ct%3D______%EF%BC%8E)
∵等比数列{an}的前n项和为Sn=32n+1+t,
∴a1=s1=27+t,
a2=s2-a1=72,
an=sn-sn-1=8×32n-1,
∴27+t=24,
∴t=-3,
q=
72
24=3,
故答案为:3;-3
∴a1=s1=27+t,
a2=s2-a1=72,
an=sn-sn-1=8×32n-1,
∴27+t=24,
∴t=-3,
q=
72
24=3,
故答案为:3;-3
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