(-1/2x^3-3/2xy+1/4y^2)(-2xy^2)^2计算
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(-1/2x^3-3/2xy+1/4y^2)(-2xy^2)^2计算
![(-1/2x^3-3/2xy+1/4y^2)(-2xy^2)^2计算](/uploads/image/z/17921246-14-6.jpg?t=%28-1%2F2x%5E3-3%2F2xy%2B1%2F4y%5E2%29%28-2xy%5E2%29%5E2%E8%AE%A1%E7%AE%97)
(-1/2x^3-3/2xy+1/4y^2)(-2xy^2)^2
= (-1/2x^3-3/2xy+1/4y^2)(4x^2y^4)
=-2x^5y^4-6x^3y^5+x^2y^6
如果本题有什么不明白可以追问,
另外发并点击我的头像向我求助,请谅解,
= (-1/2x^3-3/2xy+1/4y^2)(4x^2y^4)
=-2x^5y^4-6x^3y^5+x^2y^6
如果本题有什么不明白可以追问,
另外发并点击我的头像向我求助,请谅解,
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