5x^2-4xy+y^2-2x+1=0求(x-y)^2010的值
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5x^2-4xy+y^2-2x+1=0求(x-y)^2010的值
![5x^2-4xy+y^2-2x+1=0求(x-y)^2010的值](/uploads/image/z/17879623-7-3.jpg?t=5x%5E2-4xy%2By%5E2-2x%2B1%3D0%E6%B1%82%EF%BC%88x-y%29%5E2010%E7%9A%84%E5%80%BC)
5x^2-4xy+y^2-2x+1=0
(4x^2-4xy+y^2)+(x^2-2x+1)=0
(2x-y)^2+(x-1)^2=0
2x-y=0,x-1=0
x=1,y=2.
(x-y)^2010=(1-2)^2010=1
(4x^2-4xy+y^2)+(x^2-2x+1)=0
(2x-y)^2+(x-1)^2=0
2x-y=0,x-1=0
x=1,y=2.
(x-y)^2010=(1-2)^2010=1
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