3x^2-[7x-(4x-2)-2x^2]计算
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3x^2-[7x-(4x-2)-2x^2]计算
![3x^2-[7x-(4x-2)-2x^2]计算](/uploads/image/z/17859163-67-3.jpg?t=3x%5E2-%5B7x-%284x-2%29-2x%5E2%5D%E8%AE%A1%E7%AE%97)
3x^2-[7x-(4x-2)-2x^2]
=3x^2-[7x-4x+2-2x^2]
=3x^2-[3x+2-2x^2]
=3x^2-3x-2+2x^2
=3x^2+2x^2-3x-2
=5x^2-3x-2
再问: (-x^2++4x)+(5x-4+2x^2)化简
再答: (-x^2+4x)+(5x-4+2x^2) =-x^2+4x+5x-4+2x^2 =2x^2-x^2+4x+5x-4 =x^2+9x-4
再问: 是(-x^2+5+4x)+(5x-4+2x^2)化简
再答: (-x^2+5+4x)+(5x-4+2x^2) =-x^2+5+4x+5x-4+2x^2 =2x^2-x^2+4x+5x+5-4 =x^2+9x+1
=3x^2-[7x-4x+2-2x^2]
=3x^2-[3x+2-2x^2]
=3x^2-3x-2+2x^2
=3x^2+2x^2-3x-2
=5x^2-3x-2
再问: (-x^2++4x)+(5x-4+2x^2)化简
再答: (-x^2+4x)+(5x-4+2x^2) =-x^2+4x+5x-4+2x^2 =2x^2-x^2+4x+5x-4 =x^2+9x-4
再问: 是(-x^2+5+4x)+(5x-4+2x^2)化简
再答: (-x^2+5+4x)+(5x-4+2x^2) =-x^2+5+4x+5x-4+2x^2 =2x^2-x^2+4x+5x+5-4 =x^2+9x+1
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