tanx=-2√2,求(2cos^x/2-sinx-1)/√2sin(л/4+x)
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tanx=-2√2,求(2cos^x/2-sinx-1)/√2sin(л/4+x)
![tanx=-2√2,求(2cos^x/2-sinx-1)/√2sin(л/4+x)](/uploads/image/z/17808459-51-9.jpg?t=tanx%3D-2%E2%88%9A2%2C%E6%B1%82%282cos%5Ex%2F2-sinx-1%29%2F%E2%88%9A2sin%28%D0%BB%2F4%2Bx%29)
(2cos^x/2-sinx-1)/√2sin(л/4+x)
=(cosx-sinx)/根号2( 根号2/2cosx+sinx*根号2/2)
=(cosx-sinx)/(cosx+sinx)
=(1-tanx)/(1+tanx),(上下同除以cosx)
=(1+2根号2)/(1-2根号2)
=(1+8+4根号2)/(1-8)
=(9+4根号2)/(-7)
=(cosx-sinx)/根号2( 根号2/2cosx+sinx*根号2/2)
=(cosx-sinx)/(cosx+sinx)
=(1-tanx)/(1+tanx),(上下同除以cosx)
=(1+2根号2)/(1-2根号2)
=(1+8+4根号2)/(1-8)
=(9+4根号2)/(-7)
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