计算(x²y/-4x)²·(-2x/ay)²÷(-y/2ax²)².
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计算(x²y/-4x)²·(-2x/ay)²÷(-y/2ax²)².
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数学之美团为你解答
原式 = (x⁴y²)/(16x²) · (4x²)/(a²y²) · (4a²x⁴)/y² = x⁸ / y²
原式 = (x⁴y²)/(16x²) · (4x²)/(a²y²) · (4a²x⁴)/y² = x⁸ / y²
因式分解4x²+4xy-2ax+2bx+y²-ay+by-ab
已知曲线C:x²+y²-4ax+2ay-20+20a=0
化简(a-b)²÷(ax+by-ay-xy)-(a-b)÷(x-y)
设集合A={(X,Y) / ay²-x-1=0},B={(x,y) / 4x²+2x-2y+5=0}
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