求下列极限:lim(n×sinπ/n)
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求下列极限:lim(n×sinπ/n)
lim<n→∞>(nsinπ/n)
lim<n→∞>(nsinπ/n)
![求下列极限:lim(n×sinπ/n)](/uploads/image/z/17758039-31-9.jpg?t=%E6%B1%82%E4%B8%8B%E5%88%97%E6%9E%81%E9%99%90%3Alim%EF%BC%88n%C3%97sin%CF%80%2Fn%29)
当n→∞时,π/n →0,则sinπ/n等价于π/n
则lim(n×sinπ/n)
=limn×(π/n)
= π
则lim(n×sinπ/n)
=limn×(π/n)
= π
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