若(x-1)2+|y+2|=0,则(x+y)2013=______.
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若(x-1)2+|y+2|=0,则(x+y)2013=______.
![若(x-1)2+|y+2|=0,则(x+y)2013=______.](/uploads/image/z/17736549-69-9.jpg?t=%E8%8B%A5%EF%BC%88x-1%EF%BC%892%2B%7Cy%2B2%7C%3D0%EF%BC%8C%E5%88%99%EF%BC%88x%2By%EF%BC%892013%3D______%EF%BC%8E)
根据题意得:
x−1=0
y+2=0,
解得:
x=1
y=−2,
则原式=(1-2)2013=-1.
故答案是:-1.
x−1=0
y+2=0,
解得:
x=1
y=−2,
则原式=(1-2)2013=-1.
故答案是:-1.
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