若a+3b=0,则[1-b/a+2b]÷a+2ab+b/a-4b=?
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若a+3b=0,则[1-b/a+2b]÷a+2ab+b/a-4b=?
![若a+3b=0,则[1-b/a+2b]÷a+2ab+b/a-4b=?](/uploads/image/z/17697010-58-0.jpg?t=%E8%8B%A5a%2B3b%3D0%2C%E5%88%99%5B1-b%2Fa%2B2b%5D%C3%B7a%2B2ab%2Bb%2Fa-4b%3D%3F)
若a+3b=0,则[1-(b/a+2b)]÷[(a+2ab+b)/(a-4b)]=?a+3b=0 a=-3b 原式=[(a+2b-b)/(a+2b)]÷(a+b)^2/(a+2b)(a-2b) =(a+b)/(a+2b)×(a+2b)(a-2b)/(a+b)^2 =(a-2b)/(a+b) =(-3b-2b)/(-3b+b) =-5b/(-2b) =5/2
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