8、若 y,z均为质数,x=yz且 x,y,z 满足 1/x+1/y=3/z,则1998x+5y+3z=
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8、若 y,z均为质数,x=yz且 x,y,z 满足 1/x+1/y=3/z,则1998x+5y+3z=
若a,b,c均为质数,x=yz且x,y,z满足1/x+1/y=3/z,则1998x+5y+3z=
若a,b,c均为质数,x=yz且x,y,z满足1/x+1/y=3/z,则1998x+5y+3z=
![8、若 y,z均为质数,x=yz且 x,y,z 满足 1/x+1/y=3/z,则1998x+5y+3z=](/uploads/image/z/17656177-49-7.jpg?t=8%E3%80%81%E8%8B%A5+y%2Cz%E5%9D%87%E4%B8%BA%E8%B4%A8%E6%95%B0%2Cx%3Dyz%E4%B8%94+x%2Cy%2Cz+%E6%BB%A1%E8%B6%B3+1%2Fx%2B1%2Fy%3D3%2Fz%2C%E5%88%991998x%2B5y%2B3z%3D)
x = yz
1/x+1/y=3/z
1/yz + z/yz = 3y/yz ====> 3y = z+1因为y是质数,如果y是奇数的质数,z= 3y-1必为偶数,不成立
所以y为偶数的质数,也就是y=2 z = 5 x = 10
1998x+5y+3z= 19980 + 10 + 15 = 20005
1/x+1/y=3/z
1/yz + z/yz = 3y/yz ====> 3y = z+1因为y是质数,如果y是奇数的质数,z= 3y-1必为偶数,不成立
所以y为偶数的质数,也就是y=2 z = 5 x = 10
1998x+5y+3z= 19980 + 10 + 15 = 20005
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