已知sin(π+α)=1/4,求sin(2π-α)-cot(α-π)cosα的值
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已知sin(π+α)=1/4,求sin(2π-α)-cot(α-π)cosα的值
![已知sin(π+α)=1/4,求sin(2π-α)-cot(α-π)cosα的值](/uploads/image/z/17653372-52-2.jpg?t=%E5%B7%B2%E7%9F%A5sin%28%CF%80%2B%CE%B1%29%3D1%2F4%2C%E6%B1%82sin%282%CF%80-%CE%B1%29-cot%28%CE%B1-%CF%80%29cos%CE%B1%E7%9A%84%E5%80%BC)
sin(π+α)=1/4,sina=-1/4
sin(2π-α)-cot(α-π)cosα
=-sina+cot(∏-a)cosa
=-sina-cotacosa
=-sina-cosa/sina*cosa
=1/4-(cosa)^2/(-1/4)
=1/4+4[1-(sina)^2]
=1/4+4(1-1/16)
=4
sin(2π-α)-cot(α-π)cosα
=-sina+cot(∏-a)cosa
=-sina-cotacosa
=-sina-cosa/sina*cosa
=1/4-(cosa)^2/(-1/4)
=1/4+4[1-(sina)^2]
=1/4+4(1-1/16)
=4
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