已知整式6x-1的值是2,y²的值是4,则(5x²y+5xy-7x)-(4x²y+5xy-
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已知整式6x-1的值是2,y²的值是4,则(5x²y+5xy-7x)-(4x²y+5xy-7x)=
![已知整式6x-1的值是2,y²的值是4,则(5x²y+5xy-7x)-(4x²y+5xy-](/uploads/image/z/17636582-38-2.jpg?t=%E5%B7%B2%E7%9F%A5%E6%95%B4%E5%BC%8F6x-1%E7%9A%84%E5%80%BC%E6%98%AF2%2Cy%26%23178%3B%E7%9A%84%E5%80%BC%E6%98%AF4%2C%E5%88%99%EF%BC%885x%26%23178%3By%2B5xy-7x%29-%284x%26%23178%3By%2B5xy-)
6x-1=2
x=1/2
y^2-y=2
y^2-y-2=0
(y-2)(y+1)=0
y=2或y=-1
(5x的平方y+5xy-7x)-(4x的平方y+5xy-7x)
=5x^2y+5xy-7x-4x^2y-5xy+7x
=x^2y
x^2y=(1/2)^2*2 =1/2
或x^2y=(1/2)^2*(-1) =-1/4
x=1/2
y^2-y=2
y^2-y-2=0
(y-2)(y+1)=0
y=2或y=-1
(5x的平方y+5xy-7x)-(4x的平方y+5xy-7x)
=5x^2y+5xy-7x-4x^2y-5xy+7x
=x^2y
x^2y=(1/2)^2*2 =1/2
或x^2y=(1/2)^2*(-1) =-1/4
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