已知tana=1求√2sin(2a+π/4)+1
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已知tana=1求√2sin(2a+π/4)+1
![已知tana=1求√2sin(2a+π/4)+1](/uploads/image/z/17602288-16-8.jpg?t=%E5%B7%B2%E7%9F%A5tana%3D1%E6%B1%82%E2%88%9A2sin%EF%BC%882a%2B%CF%80%2F4%29%2B1)
tana=1 a=π/4+kπ(k∈Z)
√2sin(2a+π/4)+1 = √2sin[2x(π/4+kπ)+π/4]+1
= √2sin(π/2+π/4+2kπ)+1
=√2 sin3/4π+1
=√2 x √2/2 +1
=2
√2sin(2a+π/4)+1 = √2sin[2x(π/4+kπ)+π/4]+1
= √2sin(π/2+π/4+2kπ)+1
=√2 sin3/4π+1
=√2 x √2/2 +1
=2
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