x²-xy-3x=0,x²+y+1=0
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x²-xy-3x=0,x²+y+1=0
![x²-xy-3x=0,x²+y+1=0](/uploads/image/z/17575375-31-5.jpg?t=x%26%23178%3B-xy-3x%3D0%2Cx%26%23178%3B%2By%2B1%3D0)
由x²+y+1=0,得y=-x²-1,代入x²-xy-3x=0,得:
x²-x(-x²-1)-3x=0
x³+x²-2x=0
x(x²+x-2)=0
x(x+2)(x-1)=0 得出:x=0,1,-2
x=0时:y=-x²-1=-1
x=1时:y=-x²-1=-2
x=-2时:y=-x²-1=-5
x²-x(-x²-1)-3x=0
x³+x²-2x=0
x(x²+x-2)=0
x(x+2)(x-1)=0 得出:x=0,1,-2
x=0时:y=-x²-1=-1
x=1时:y=-x²-1=-2
x=-2时:y=-x²-1=-5
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