这两道题该怎么化简呢,请回答者不要省略过程,
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:数学作业 时间:2024/07/08 13:17:28
这两道题该怎么化简呢,请回答者不要省略过程,
![](http://img.wesiedu.com/upload/9/06/906db470278b2e2d3f2e6e2e65e86455.jpg)
![](http://img.wesiedu.com/upload/b/e9/be9e9d651104f7ccff9e0db86645bea2.jpg)
![](http://img.wesiedu.com/upload/9/06/906db470278b2e2d3f2e6e2e65e86455.jpg)
![](http://img.wesiedu.com/upload/b/e9/be9e9d651104f7ccff9e0db86645bea2.jpg)
![这两道题该怎么化简呢,请回答者不要省略过程,](/uploads/image/z/17528793-33-3.jpg?t=%E8%BF%99%E4%B8%A4%E9%81%93%E9%A2%98%E8%AF%A5%E6%80%8E%E4%B9%88%E5%8C%96%E7%AE%80%E5%91%A2%2C%E8%AF%B7%E5%9B%9E%E7%AD%94%E8%80%85%E4%B8%8D%E8%A6%81%E7%9C%81%E7%95%A5%E8%BF%87%E7%A8%8B%2C)
解第1题
原式=(√y)/(√x+√y)-[√(xy)-(x√y)/(√x+√y)]÷√(xy)
=(√y)/(√x+√y)-[√(xy)×1/√(xy)-(x√y)/(√x+√y)×1/√(xy)]
=(√y)/(√x+√y)-[1-√x×√(xy)/(√x+√y)×1/√(xy)]
=(√y)/(√x+√y)-[1-(√x)/(√x+√y)]
=(√y)/(√x+√y)+(√x)/(√x+√y)-1
=(√x+√y)/(√x+√y)-1
=1-1
=0
解第2题:
a=1/√3=(√3)/3﹤1
原式=(1-2a+a²)/(a-1)-[√(a²-2a+1)]/(a²-a)
=(a-1)²/(a-1)-[√(a-1)²]/[a(a-1)]
=a-1-|a-1|/[a(a-1)]
=a-1+(a-1)/[a(a-1)]
=a-1+(1/a)
当a=(√3)/3时
原式=(√3)/3-1+√3
=(√3-3+3√3)/3
=(4√3-3)/3
原式=(√y)/(√x+√y)-[√(xy)-(x√y)/(√x+√y)]÷√(xy)
=(√y)/(√x+√y)-[√(xy)×1/√(xy)-(x√y)/(√x+√y)×1/√(xy)]
=(√y)/(√x+√y)-[1-√x×√(xy)/(√x+√y)×1/√(xy)]
=(√y)/(√x+√y)-[1-(√x)/(√x+√y)]
=(√y)/(√x+√y)+(√x)/(√x+√y)-1
=(√x+√y)/(√x+√y)-1
=1-1
=0
解第2题:
a=1/√3=(√3)/3﹤1
原式=(1-2a+a²)/(a-1)-[√(a²-2a+1)]/(a²-a)
=(a-1)²/(a-1)-[√(a-1)²]/[a(a-1)]
=a-1-|a-1|/[a(a-1)]
=a-1+(a-1)/[a(a-1)]
=a-1+(1/a)
当a=(√3)/3时
原式=(√3)/3-1+√3
=(√3-3+3√3)/3
=(4√3-3)/3