3x²y²+2xy-7x²y²-3/2xy+2+4x²y²,
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3x²y²+2xy-7x²y²-3/2xy+2+4x²y²,其中x=2,y=1/4
请问那题怎么解答?
请问那题怎么解答?
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3x²y²+2xy-7x²y²-3/2xy+2+4x²y²
=(3+4-7)x²y²+(2-3/2)xy+2
=1/2xy+2
=2又1/4
再问: 若a²b m和a n b³是同类项,则m n=_______.
再答: a²b^m 与a^nb³是同类项, 则n=2,m=3 所以m-n=3-2=1
=(3+4-7)x²y²+(2-3/2)xy+2
=1/2xy+2
=2又1/4
再问: 若a²b m和a n b³是同类项,则m n=_______.
再答: a²b^m 与a^nb³是同类项, 则n=2,m=3 所以m-n=3-2=1
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