[(x^2n+2)^2-(x^2n-2)^2]/[(x^n+1)^2+(x^n-1)^2]的极限
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:数学作业 时间:2024/07/21 05:44:55
[(x^2n+2)^2-(x^2n-2)^2]/[(x^n+1)^2+(x^n-1)^2]的极限
x趋近于无穷大,n是正整数
x趋近于无穷大,n是正整数
![[(x^2n+2)^2-(x^2n-2)^2]/[(x^n+1)^2+(x^n-1)^2]的极限](/uploads/image/z/17503585-25-5.jpg?t=%5B%28x%5E2n%2B2%29%5E2-%28x%5E2n-2%29%5E2%5D%2F%5B%28x%5En%2B1%29%5E2%2B%28x%5En-1%29%5E2%5D%E7%9A%84%E6%9E%81%E9%99%90)
用平方差公式,分子为8x^2n.分母最高次项为2x^2n,故所求极限为8/2=4.
求x趋近于0时候的极限 [(n!)^(-1) * n^(-n) * (2n)!]^(1/n)
求极限lim [x^(n+1)-(n+1)x+n]/(x-1)^2 x趋于1
求极限lim(x→∞)(1/n+2/n+3/n..+n/n)
lim[n/(n*n+1*1)+n/(n*n+2*2)+...+n/(n*n+n*n)],当x趋向无穷大时,怎么求极限,
几道高数求极限的题 1 x趋于1时,(x+x^2+...+x^n)/(x-1)的极限2 n趋于无穷时,(n*tan1/n
求极限lim(-2)^n+3^n/(-2)^[n+1]+3^[n+1] (x→∞)
求极限:lim(x→无穷)(2^n-7^n)/(2^n+7^n-1)=?
x^2n(x^2-2n-2x^1-2n+x^-2n)
计算(x^(2n)+x^n+1)(x^(3n)-x^(2n)+1)
因式分解4x^(n+2)-9x^n+6x^(n-1)-x^(n-2)
求两道极限计算题:1)lim(x->1):(x^n-1)/(x-1) (n属于自然数集,x^n表示x的n次方)2)lim
求x趋于1,lim(x+x^2+……+x^n-n)/(x-1)的极限,