1元2次方程.用适当的方法解方程.
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:数学作业 时间:2024/07/24 20:44:25
1元2次方程.用适当的方法解方程.
(1) (3y - 1)² -25=0 (2) .x² - 4x= -2
(3) 3x² - 13x +4 = 0 (4) 2t² - 4 = 7t
(5) 3x² - 5x -2 = 0 (6) x² - 6x + 1 =0
(1) (3y - 1)² -25=0 (2) .x² - 4x= -2
(3) 3x² - 13x +4 = 0 (4) 2t² - 4 = 7t
(5) 3x² - 5x -2 = 0 (6) x² - 6x + 1 =0
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(1) (3y - 1)² -25=0
y²- 2*3y*1+1-25=0
y²- 6y-24=0
(3y - 4)(3y - 6)=0
3y - 4 =0
3y - 6=0
y²- 2*3y*1+1-25=0
y²- 6y-24=0
(3y - 4)(3y - 6)=0
3y - 4 =0
3y - 6=0