解方程组4/x^2+25/y^2=25,2/x+5/y=1
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解方程组4/x^2+25/y^2=25,2/x+5/y=1
![解方程组4/x^2+25/y^2=25,2/x+5/y=1](/uploads/image/z/17258917-13-7.jpg?t=%E8%A7%A3%E6%96%B9%E7%A8%8B%E7%BB%844%2Fx%5E2%2B25%2Fy%5E2%3D25%2C2%2Fx%2B5%2Fy%3D1)
设1/ x=m 1/y=n 原方程转换为4m^2+25n^2=25,2m+5n=1 m=(1-5n)/2 4*[(1-5n)/2]^2+25n^2=25 25n^2-5n-12=0 (5n-4)(5n+3)=0 n=4/5或n=-3/5 m=-3/2或m=2 n=4/5,m=-3/2 或n=-3/5,m=2 x=-2/3,y=5/4 或x=1/2,y=-5/3
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