证明恒等式(1+sin2a-cos2a)/(1+sin2a+cos2s)=tana
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证明恒等式(1+sin2a-cos2a)/(1+sin2a+cos2s)=tana
tana+cota=2/sin2a
tana+cota=2/sin2a
![证明恒等式(1+sin2a-cos2a)/(1+sin2a+cos2s)=tana](/uploads/image/z/17249243-59-3.jpg?t=%E8%AF%81%E6%98%8E%E6%81%92%E7%AD%89%E5%BC%8F%EF%BC%881%2Bsin2a-cos2a%EF%BC%89%2F%281%2Bsin2a%2Bcos2s%29%3Dtana)
原式=(sinx)2+2sinxcosx/(cosx)2+2sinxcos=sin/cos=tanx
原式=sinx/cosx+cosx/sinx=1/sinxcosx=2/sin2x
原式=sinx/cosx+cosx/sinx=1/sinxcosx=2/sin2x
证明 2(sin2a+1)/1+sin2a+cos2a=tana+1
求证:1+sin2a-cos2a/1+sin2a+cos2a=tana
求证1+sin2a-cos2a除以1+sin2a+cos2a=tana
求证:2(sin2a+1)/(1+sin2a+cos2a)=tana+1
证明:(sin2a+1)/(sin2a+cos2a+1)=1/2(tana+1)
1+sin2a-cos2a/1+sin2a+cos2a为什么等于tana?
求证:1+sin2a/cos2a=1+tana/1-tana
1.化简[2sin2a/(1+cos2a)]*1/tana
已知2sin2a+1=cos2a,求tana的值
化简:(1+sin2a-cos2a)/(1+sin2a+cos2a)
化简:(1+cos2a)/sin2a-sin2a/(1-cos2a)=
化简:(1+sin2a+cos2a)/(1+sin2a-cos2a)