求不定积分题解过程
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求不定积分题解过程
![](http://img.wesiedu.com/upload/0/92/0928377746919456d7bc0bb3b025b0f1.jpg)
![](http://img.wesiedu.com/upload/0/92/0928377746919456d7bc0bb3b025b0f1.jpg)
![求不定积分题解过程](/uploads/image/z/17246718-54-8.jpg?t=%E6%B1%82%E4%B8%8D%E5%AE%9A%E7%A7%AF%E5%88%86%E9%A2%98%E8%A7%A3%E8%BF%87%E7%A8%8B)
Let t=(2x-1)^(1/2)
then t^2+1=2x dx=tdt
so ∫e^[(2x-1)^(1/2)]dx
=∫te^tdt=te^t-∫e^tdt
=(t-1)e^t+C
=[(2x-1)^(1/2)-1]*e^[(2x-1)^(1/2)]+C
then t^2+1=2x dx=tdt
so ∫e^[(2x-1)^(1/2)]dx
=∫te^tdt=te^t-∫e^tdt
=(t-1)e^t+C
=[(2x-1)^(1/2)-1]*e^[(2x-1)^(1/2)]+C