3分之7π怎样算?整道题是cos7π/3+tan(-15π/4),我想要计算过程,还有tan225°×cos240°×s
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:数学作业 时间:2024/07/03 10:06:39
3分之7π怎样算?
整道题是cos7π/3+tan(-15π/4),我想要计算过程,还有tan225°×cos240°×sin(-60°)×tan(-30°)
整道题是cos7π/3+tan(-15π/4),我想要计算过程,还有tan225°×cos240°×sin(-60°)×tan(-30°)
(1)cos7π/3+tan(-15π/4)
=cos(2π+π/3)+tan(-4π+π/4)
=cosπ/3+tanπ/4
=1/2+1=3/2
(2)tan225°×cos240°×sin(-60°)×tan(-30°)
=tan(180º+45º)×cos(180º+60º)×(-sin60º)×(-tan30º)
=tan45º×(-cos60º)×(-√3/2)(-√3/3)
=1×(-1/2)×1/2=-1/4
再问: 谢谢你!还想问一下 sin(-π/3)+2sin4π/3+3sin2π/3 谢谢!
再答: sin(-π/3)+2sin4π/3+3sin2π/3 =-sinπ/3+2sin(π+π/3)+3sin(π-π/3) =-sinπ/3-2sinπ/3+3sinπ/3=0
=cos(2π+π/3)+tan(-4π+π/4)
=cosπ/3+tanπ/4
=1/2+1=3/2
(2)tan225°×cos240°×sin(-60°)×tan(-30°)
=tan(180º+45º)×cos(180º+60º)×(-sin60º)×(-tan30º)
=tan45º×(-cos60º)×(-√3/2)(-√3/3)
=1×(-1/2)×1/2=-1/4
再问: 谢谢你!还想问一下 sin(-π/3)+2sin4π/3+3sin2π/3 谢谢!
再答: sin(-π/3)+2sin4π/3+3sin2π/3 =-sinπ/3+2sin(π+π/3)+3sin(π-π/3) =-sinπ/3-2sinπ/3+3sinπ/3=0
确定cos7/12π,sin(-465°),tan11/3π,sin3*cos4*tan5的符号
计算sin(-α-5π)*cos(α-2分之π)-tan(α-2分之3π)*tan(2π-α)
有关复数的题目一.计算:1) 根根根(-1),并作出图形.2) [12(cos7π/4+isin7π/4)]/[6(co
sin100°*cos240°如何化简
请问15分之8+3分之2-4分之3有简便计算吗?如果有简便计算,请问应该怎样简便计算?要具体的过程,
化简计算sin6分之25π+cos3分之25π+tan(-4分之25π)
计算cosπ/8的四次方+cos3π/8的四次方+5π/8的四次方+cos7π/8的四次方之和
三角函数的计算题目cos25/3*π=tan(-15/4*π)
已知sinθ=5分之3,θ∈(2分之π,π),tanψ=2分之1,求tan(θ+ψ),tan(θ-ψ)的值
3分之10乘7分之3加3分之20乘7分之3用简便方法算 还有5分之19乘9乘分之1加5分之1除以9用简便计算要写出过程
9分之8【4分之3-(16分之7-4分之1)】 脱式计算,怎样简便怎样算
1sin3分之4π乘以6分之cos25π乘以tan-4分之3π=