|ab-2|+|b-1|=0 1/ab+1/(a+b)(b+1)+1/(a+2)(b+2)+''''''+1/(a+20
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|ab-2|+|b-1|=0 1/ab+1/(a+b)(b+1)+1/(a+2)(b+2)+''''''+1/(a+2008)(b+2008)=?
![|ab-2|+|b-1|=0 1/ab+1/(a+b)(b+1)+1/(a+2)(b+2)+''''''+1/(a+20](/uploads/image/z/17143188-60-8.jpg?t=%7Cab-2%7C%2B%7Cb-1%7C%3D0+1%2Fab%2B1%2F%28a%2Bb%29%28b%2B1%29%2B1%2F%28a%2B2%29%28b%2B2%29%2B%27%27%27%27%27%27%2B1%2F%28a%2B20)
绝对值为非负数,和为0只有分别等于0
ab-2=0,b-1=0
b=1,a=2
原式=1/1×2+1/2×3+1/3×4+1/2009×2010
=1-1/2+1/2-1/3+...+1/2009-1/2010
=1-1/2010
=2009/2010
ab-2=0,b-1=0
b=1,a=2
原式=1/1×2+1/2×3+1/3×4+1/2009×2010
=1-1/2+1/2-1/3+...+1/2009-1/2010
=1-1/2010
=2009/2010
计算ab/(a+b-1)(a+b)+ab/(a+b)(a+b+1)+ab/(a+b+1)(a+b+2)+.+ab/(a+
a(a-1)-(a×a-b)=-5,求(a×a+b×b)÷2-ab
[a+b][a^2-ab+b^2]+ab-a^2-b^2为什么等于[a^2-ab-b^2][a+b-1]=0
求证:A/(AB+B^2)-B/(AB+A^2)=1/B-1/A
如果a+b=3,ab=-1,那么(a+b)2-a-b+ab=?
ab+a+b+1
已知(3a-b+1)的绝对值+(3a-b/2)^2=0求b^2/a+b除以(b/a+b*ab/a+b)的值
1.已知A-B=-根号2 AB=1/3求代数式 (A-B)+A*A+B*B+AB
先化简,再求值:[a/(a+b)-b/(b-a)-2ab/(a^2-b^2)]/(1/a-1/b),其中a+b=3,ab
急……ab/(a+b-1)(a+b) + ab/(a+b)(a+b+1) + ab(a+b+1)(a+b+2) + ……
把B=A^2/(A+1)代入【(B-A)/AB】[1-(A-B)]求值.
已知a-b=4,ab=-1,求(-2ab+2a+3b)-(a-4b+b)