求道三角函数题的解法1.若f(sina)=2-cos2a 则f(cosa)=?2.sin7°+cos15°sin8°/c
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求道三角函数题的解法
1.若f(sina)=2-cos2a 则f(cosa)=?
2.sin7°+cos15°sin8°/cos7°-sin15°sin8°
sin7°+cos15°×sin8°
----------------------------
cos7°-sin15°×sin8°
1.若f(sina)=2-cos2a 则f(cosa)=?
2.sin7°+cos15°sin8°/cos7°-sin15°sin8°
sin7°+cos15°×sin8°
----------------------------
cos7°-sin15°×sin8°
![求道三角函数题的解法1.若f(sina)=2-cos2a 则f(cosa)=?2.sin7°+cos15°sin8°/c](/uploads/image/z/17111186-26-6.jpg?t=%E6%B1%82%E9%81%93%E4%B8%89%E8%A7%92%E5%87%BD%E6%95%B0%E9%A2%98%E7%9A%84%E8%A7%A3%E6%B3%951.%E8%8B%A5f%28sina%29%3D2-cos2a+%E5%88%99f%28cosa%29%3D%3F2.sin7%C2%B0%2Bcos15%C2%B0sin8%C2%B0%2Fc)
1.f(sina)=2-cos2a =(sina)^2+1
f(x)=x^2+1
f(cosa)=(cosa)^2+1
2.题目打得太乱了= =
f(x)=x^2+1
f(cosa)=(cosa)^2+1
2.题目打得太乱了= =
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