如果有理数a,b满足|ab-2|+(1-b)的2次方=0,试求:1/ab+1/(a+1)(b+1)+1/(a+2)(b+
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如果有理数a,b满足|ab-2|+(1-b)的2次方=0,试求:1/ab+1/(a+1)(b+1)+1/(a+2)(b+2)+……+1/(a+2007)(b+200
![如果有理数a,b满足|ab-2|+(1-b)的2次方=0,试求:1/ab+1/(a+1)(b+1)+1/(a+2)(b+](/uploads/image/z/17063591-23-1.jpg?t=%E5%A6%82%E6%9E%9C%E6%9C%89%E7%90%86%E6%95%B0a%2Cb%E6%BB%A1%E8%B6%B3%7Cab-2%7C%2B%EF%BC%881-b%29%E7%9A%842%E6%AC%A1%E6%96%B9%3D0%2C%E8%AF%95%E6%B1%82%EF%BC%9A1%2Fab%2B1%2F%28a%2B1%29%28b%2B1%29%2B1%2F%28a%2B2%29%28b%2B)
ab=2
b=1
a=2
f(x)=1/2+1/(2*3)+1/(3*4)+.+1/(2008*2009)
f(x)=1/2+1/2-1/3+1/3-1/4+.+1/2008-1/2009
f(x)=1-1/2009=2008/2009
b=1
a=2
f(x)=1/2+1/(2*3)+1/(3*4)+.+1/(2008*2009)
f(x)=1/2+1/2-1/3+1/3-1/4+.+1/2008-1/2009
f(x)=1-1/2009=2008/2009
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