(2007•金山区一模)设函数f(x)=1+2cos(2x−π4)sin(x+π2).
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(2007•金山区一模)设函数f(x)=
1+
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sin(x+
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![(2007•金山区一模)设函数f(x)=1+2cos(2x−π4)sin(x+π2).](/uploads/image/z/17057041-25-1.jpg?t=%EF%BC%882007%E2%80%A2%E9%87%91%E5%B1%B1%E5%8C%BA%E4%B8%80%E6%A8%A1%EF%BC%89%E8%AE%BE%E5%87%BD%E6%95%B0f%EF%BC%88x%EF%BC%89%3D1%2B2cos%282x%E2%88%92%CF%804%29sin%28x%2B%CF%802%29%EF%BC%8E)
(1)函数f(x)=
1+cos2x+sin2x
cosx
=
2cos2x+2sinxcosx
cosx
=2sinx+2cosx …(5分)
f(x)的定义域为{x|x≠kπ+
π
2,k∈Z},…(6分)
又f(x)=2
2sin(x+
π
4),…(7分)
f(x)max=2
2,f(x)min=-2
2;…(9分)
(2)若锐角α满足cosα=
4
5,则sinα=
3
5,…(10分)
则f(α)=2sinα+2cosα=
14
5.…(12分)
1+cos2x+sin2x
cosx
=
2cos2x+2sinxcosx
cosx
=2sinx+2cosx …(5分)
f(x)的定义域为{x|x≠kπ+
π
2,k∈Z},…(6分)
又f(x)=2
2sin(x+
π
4),…(7分)
f(x)max=2
2,f(x)min=-2
2;…(9分)
(2)若锐角α满足cosα=
4
5,则sinα=
3
5,…(10分)
则f(α)=2sinα+2cosα=
14
5.…(12分)
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