计算f(x)=e^-x *ln(2-x)+√(1+3x^2),求f'(1)
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计算f(x)=e^-x *ln(2-x)+√(1+3x^2),求f'(1)
![计算f(x)=e^-x *ln(2-x)+√(1+3x^2),求f'(1)](/uploads/image/z/17028241-25-1.jpg?t=%E8%AE%A1%E7%AE%97f%28x%29%3De%5E-x+%2Aln%282-x%29%2B%E2%88%9A%281%2B3x%5E2%29%2C%E6%B1%82f%27%281%29)
f'(x) = -e^-x *ln(2-x) + e^-x *(-1)/(2-x) + 1/2*(1+3x^2)^(-1/2)*6x,
f'(1) = 0 - e^-1 + 1/2*(1+3)^(-1/2)*6
= -1/e + 3/2
f'(1) = 0 - e^-1 + 1/2*(1+3)^(-1/2)*6
= -1/e + 3/2
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