已知log2[log1/2(log2x)]=log3[log1/3(log3y)]=log5[log1/5(log5z)
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已知log2[log1/2(log2x)]=log3[log1/3(log3y)]=log5[log1/5(log5z)]=0.求x2+y^3-z^5的值
![已知log2[log1/2(log2x)]=log3[log1/3(log3y)]=log5[log1/5(log5z)](/uploads/image/z/17012254-22-4.jpg?t=%E5%B7%B2%E7%9F%A5log2%5Blog1%2F2%28log2x%29%5D%3Dlog3%5Blog1%2F3%28log3y%29%5D%3Dlog5%5Blog1%2F5%28log5z%29)
log2[log1/2(log2x)]=0=log2(1)
log1/2(log2x)=1=log1/2(1/2)
log2(x)=1/2
x=2^(1/2)
log3[log1/3(log3y)]=0
log1/3(log3y)=1
log3(y)=1/3
y=3^(1/3)
x^6=2^3=8
y^6=3^2=9
所以y>x
log5[log1/5(log5z)]=o
log1/5(log5z)=1
log5(z)=1/5
z=5^(1/5)
x^2=2
y^3=3
z^5=5
x2+y^3-z^5=2+3-5=0
log1/2(log2x)=1=log1/2(1/2)
log2(x)=1/2
x=2^(1/2)
log3[log1/3(log3y)]=0
log1/3(log3y)=1
log3(y)=1/3
y=3^(1/3)
x^6=2^3=8
y^6=3^2=9
所以y>x
log5[log1/5(log5z)]=o
log1/5(log5z)=1
log5(z)=1/5
z=5^(1/5)
x^2=2
y^3=3
z^5=5
x2+y^3-z^5=2+3-5=0
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