社无穷等差数列an的前n项和为Sn,若不等式an^2+Sn^2/n^2>=t/5a1^2
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:数学作业 时间:2024/07/15 05:47:08
社无穷等差数列an的前n项和为Sn,若不等式an^2+Sn^2/n^2>=t/5a1^2
设无穷等差数列{an}的前n项和为Sn,若不等式an^2+Sn^2/n^2>=(t/5)a1^2对任意正整数n都成立,则实数t的取值范围
A.t>=1 B.t
t
设无穷等差数列{an}的前n项和为Sn,若不等式an^2+Sn^2/n^2>=(t/5)a1^2对任意正整数n都成立,则实数t的取值范围
A.t>=1 B.t
t
![社无穷等差数列an的前n项和为Sn,若不等式an^2+Sn^2/n^2>=t/5a1^2](/uploads/image/z/16997578-34-8.jpg?t=%E7%A4%BE%E6%97%A0%E7%A9%B7%E7%AD%89%E5%B7%AE%E6%95%B0%E5%88%97an%E7%9A%84%E5%89%8Dn%E9%A1%B9%E5%92%8C%E4%B8%BASn%2C%E8%8B%A5%E4%B8%8D%E7%AD%89%E5%BC%8Fan%5E2%2BSn%5E2%2Fn%5E2%3E%3Dt%2F5a1%5E2)
你是不是打错了?
A选项,是不是A t
A选项,是不是A t
设数列an的前n项和为Sn,a1=1,an=(Sn/n)+2(n-1)(n∈N*) 求证:数列an为等差数列,
等差数列{An}的前n项和为Sn,若 lim Sn/n方 =2
设数列{an}的前n项和为Sn,若对任意正整数,都有Sn=n(a1+an)/2,证明{an}是等差数列.
已知数列{an}的前n项和为Sn,且满足an+2Sn*Sn-1=0,a1=1/2.求证:{1/Sn}是等差数列
已知数列{an}的前n项和为Sn,且满足Sn=Sn-1/2Sn-1 +1,a1=2,求证{1/Sn}是等差数列
设数列an的前n项和为sn,对于所有的自然数n都有sn=n(a1+an)/2,求证an是等差数列
已知等差数列{an}的前N项和为Sn,a1=-2/3,满足Sn+1/Sn+2=an(n大于等于2)
已知等差数列{an}的前N项和为Sn,a1=-2/3,满足Sn+1/Sn+2=an(n大于等于2),
设Sn为等差数列{an}的前n项和,若a1=1,公差d=2,Sn+2-Sn=36,则n=( )
已知等差数列{an}中,a1=2,d=-2,前n项的和为 Sn,则 Sn( )
已知等差数列an中a1=2,其前n项和sn,若数列{Sn/n}构成一个公差为2的等差数列,则a3=?
数列前n项和为sn,a1=1,an+sn是公差为2的等差数列,求an-2是等比数列,并求sn