已知:x²-4x+y²-10y+29=0,求(x+y)²
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已知:x²-4x+y²-10y+29=0,求(x+y)²
![已知:x²-4x+y²-10y+29=0,求(x+y)²](/uploads/image/z/16978567-31-7.jpg?t=%E5%B7%B2%E7%9F%A5%3Ax%26%23178%3B-4x%2By%26%23178%3B-10y%2B29%3D0%2C%E6%B1%82%28x%2By%29%26%23178%3B)
即(x²-4x+4)+(y²-10y+25)=0
(x-2)²+(y-5)²=0
所以x-2=,y-5=0
所以x=2,y=5
(x+y)²=7²=49
(x-2)²+(y-5)²=0
所以x-2=,y-5=0
所以x=2,y=5
(x+y)²=7²=49
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