我就是看不懂的导数题y=e^(sinx)*cos(sinx),则y'(0)=?
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我就是看不懂的导数题
y=e^(sinx)*cos(sinx),则y'(0)=?
y=e^(sinx)*cos(sinx),则y'(0)=?
![我就是看不懂的导数题y=e^(sinx)*cos(sinx),则y'(0)=?](/uploads/image/z/16943924-20-4.jpg?t=%E6%88%91%E5%B0%B1%E6%98%AF%E7%9C%8B%E4%B8%8D%E6%87%82%E7%9A%84%E5%AF%BC%E6%95%B0%E9%A2%98y%3De%5E%28sinx%29%2Acos%28sinx%29%2C%E5%88%99y%27%280%29%3D%3F)
对x求导:
y'=e^(sinx)*[cos(sinx)]' + [e^(sinx)]' *cos(sinx)
=e^(sinx)*[-sin(sinx)]*cosx + e^(sinx)*cosx *cos(sinx)
=e^(sinx)*cosx*[cos(sinx)-sin(sinx)]
将x=0代入,可得:
y'(0)=e^0 *cos0*(cos0-sin0)
=1
y'=e^(sinx)*[cos(sinx)]' + [e^(sinx)]' *cos(sinx)
=e^(sinx)*[-sin(sinx)]*cosx + e^(sinx)*cosx *cos(sinx)
=e^(sinx)*cosx*[cos(sinx)-sin(sinx)]
将x=0代入,可得:
y'(0)=e^0 *cos0*(cos0-sin0)
=1