若x^2+4x+y^2-6Y+13=0,则(x+2y)(x-2y)的值
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若x^2+4x+y^2-6Y+13=0,则(x+2y)(x-2y)的值
![若x^2+4x+y^2-6Y+13=0,则(x+2y)(x-2y)的值](/uploads/image/z/16922857-49-7.jpg?t=%E8%8B%A5x%5E2%2B4x%2By%5E2-6Y%2B13%3D0%2C%E5%88%99%EF%BC%88x%2B2y%EF%BC%89%28x-2y%29%E7%9A%84%E5%80%BC)
x^2+4x+y^2-6Y+13=0
(x+2)^2+(y-6)^2=0
x=-2 y=6
(x+2y)(x-2y)
=x^2-4y^2
=4-144
=-140
(x+2)^2+(y-6)^2=0
x=-2 y=6
(x+2y)(x-2y)
=x^2-4y^2
=4-144
=-140
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