(log(2)9+log(4)1/9)乘以(log(3)2+log(9)0.5) 括号里是底数.计算这道题.
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(log(2)9+log(4)1/9)乘以(log(3)2+log(9)0.5) 括号里是底数.计算这道题.
log(2)9=2log(2)3=2*(lg3/lg2)
log(4)1/9=-2log(4)3=-2(lg3/lg4)=-2(lg3/2lg2)
log(9)0.5=-log(9)2=-lg2/2lg3
log(3)2=lg2/lg3
把化简的代入计算1/lg2-1/lg3或log(2)10-log(3)10
这是我化得最简结果了,就是不知道对不对了
再问: (log(2)9+log(4)1/9)*(log(3)2+log(9)0.5) =(log(2)3^2+log(4)3^-2)(log(3)2+log(9)2^-1) =(2log(2)3-2log(4)3)(log(3)2-log(9)2) =2log(2)3*log(3)2-2log(2)3*log(9)2-2log(4)3*log(3)2+2log(4)3*log(9)2 =2*lg3/lg2*lg2/lg3-2*lg3/lg2*lg2/2lg3-2*lg3/2lg2*lg2/lg3+2*lg3/2lg2*lg2/2lg3 =2-1-1+1/2 =1/2 谢谢你动手算,不过答案我算出来了!
log(4)1/9=-2log(4)3=-2(lg3/lg4)=-2(lg3/2lg2)
log(9)0.5=-log(9)2=-lg2/2lg3
log(3)2=lg2/lg3
把化简的代入计算1/lg2-1/lg3或log(2)10-log(3)10
这是我化得最简结果了,就是不知道对不对了
再问: (log(2)9+log(4)1/9)*(log(3)2+log(9)0.5) =(log(2)3^2+log(4)3^-2)(log(3)2+log(9)2^-1) =(2log(2)3-2log(4)3)(log(3)2-log(9)2) =2log(2)3*log(3)2-2log(2)3*log(9)2-2log(4)3*log(3)2+2log(4)3*log(9)2 =2*lg3/lg2*lg2/lg3-2*lg3/lg2*lg2/2lg3-2*lg3/2lg2*lg2/lg3+2*lg3/2lg2*lg2/2lg3 =2-1-1+1/2 =1/2 谢谢你动手算,不过答案我算出来了!
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