x²-4x-1=0,求(2x-3)²-(x+y)(x-y)-y²
若|x+2y-1|+y²+4y+4=0,求(2x-y)²-2(2x-y)(x+2y)+(x+2y)&
已知x²+y²+5=2x+4y,求【2x²-(x-y)(x-y)】【(x+y-1)(x-y
已知x²+y²+5=2x+4y,求代数式(2x²-(x+y)(x-y))x((x+y-1)
已知x/y=2,求2x(x+y)-y(x+y)/4x²-4xy+y²
若|x+y-1|+(x-y-2)²=0,求代数式(x+2y)(x-2y)-(2x-y)(-y-2x)的值.
已知x²+|y+x|=x-1/4,求(3x+y)²(2x-y)²-(4x²+y&
已知x²+y²+13-4x+6y=0,求(2x-y)²-2(2x-y)(x+2y)+(x+
2x²-3xy=y²=0(x,y不得o)求x/y+y/x
已知y-2x=0,求3x²-2y²/(x+y)(x-y)的值
已知实数x,y满足x²+y²-xy+2x-y+1=0 求x y
已知x²+y²-2x+4y+5=0,求x+y
x²+4y²-2x+12y+10=0求X,Y值