sinA/(1+cosA)怎么化成tan(A/2)?
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sinA/(1+cosA)怎么化成tan(A/2)?
![sinA/(1+cosA)怎么化成tan(A/2)?](/uploads/image/z/16832202-42-2.jpg?t=sinA%2F%281%2BcosA%29%E6%80%8E%E4%B9%88%E5%8C%96%E6%88%90tan%28A%2F2%29%3F)
sinA/(1+cosA)
=2sin(A/2)cos(A/2)/[1+2cos(A/2)^2-1]
=2sin(A/2)cos(A/2)/[2cos(A/2)^2]
=sin(A/2)/cos(A/2)
=tan(A/2)
=2sin(A/2)cos(A/2)/[1+2cos(A/2)^2-1]
=2sin(A/2)cos(A/2)/[2cos(A/2)^2]
=sin(A/2)/cos(A/2)
=tan(A/2)
证明(1-cos^2a)/(sina+cosa)-(sina+cosa)/(tan^2a-1)=sina+cosa
证明(1-cos^2a)/(sina-cosa)-(sina+cosa)/(tan^2-1)=sina+cosa
求证:1-cos^2a/sina-cosa - sina+cosa/tan^2a-1=sina+cosa
tan a/2=3 1-cosa-sina/1+cosa+sina
证明(1+sinA-cosA)/(1+sinA+cosA)=tan(A/2)
tan(a/2)=sina/(1+cosa)=(1-cosa)/sina
tan(a/2)=sina/(1+cosa) 怎样证明
tan(a/2)等于sina/(1+cosa)的过程
已知tan(a+π/4)=-3,则2sina-cosa/sina+cosa的值是多少?怎么算?
证明(1+sina)/cosa=(1+tan(a/2)/(1-tan(a/2))
tana+1/tana=3,求sina*cosa tan^2 a+1/tan^2 a
化简sina/(1-cosa)×根号(tan a-sina/tan a+sina)