若(x-1)^2+|y-2|=0求多项式x^2y^2-3xy+4x^2y^2-2xy+5-3x^2y^2
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若(x-1)^2+|y-2|=0求多项式x^2y^2-3xy+4x^2y^2-2xy+5-3x^2y^2
![若(x-1)^2+|y-2|=0求多项式x^2y^2-3xy+4x^2y^2-2xy+5-3x^2y^2](/uploads/image/z/16795666-10-6.jpg?t=%E8%8B%A5%28x-1%29%5E2%2B%7Cy-2%7C%3D0%E6%B1%82%E5%A4%9A%E9%A1%B9%E5%BC%8Fx%5E2y%5E2-3xy%2B4x%5E2y%5E2-2xy%2B5-3x%5E2y%5E2)
解
(x-1)²≥0
/y-2/≥0
∴x-1=0
y-2=0
∴x=1,y=2
∴原式
=(x²y²+4x²y²-3x²y²)+(-3xy-2xy)+5
=-5xy+5
=-5×2×1+5
=-10+5
=-5
(x-1)²≥0
/y-2/≥0
∴x-1=0
y-2=0
∴x=1,y=2
∴原式
=(x²y²+4x²y²-3x²y²)+(-3xy-2xy)+5
=-5xy+5
=-5×2×1+5
=-10+5
=-5
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