初二函数题目一道————————————————
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初二函数题目一道————————————————
已知y+1与z成反比例,且当y=3时,z=2;;与x-1成反比例,当x=3时,z=-4,求y关于x的解析式
已知y+1与z成反比例,且当y=3时,z=2;;与x-1成反比例,当x=3时,z=-4,求y关于x的解析式
![初二函数题目一道————————————————](/uploads/image/z/16716641-41-1.jpg?t=%E5%88%9D%E4%BA%8C%E5%87%BD%E6%95%B0%E9%A2%98%E7%9B%AE%E4%B8%80%E9%81%93%E2%80%94%E2%80%94%E2%80%94%E2%80%94%E2%80%94%E2%80%94%E2%80%94%E2%80%94%E2%80%94%E2%80%94%E2%80%94%E2%80%94%E2%80%94%E2%80%94%E2%80%94%E2%80%94)
y+1与z成反比例,设:y+1 = k/z
则:3+1 = k/2
k=8
即:y+1=8/z
z与x-1成反比例,设:z = a/(x-1)
则:-4 = a/(3-1)
a=-8
即:z=-8/(x-1)
y+1= 8/z =8/[-8/(x-1)] =-x+1
y=-x
则:3+1 = k/2
k=8
即:y+1=8/z
z与x-1成反比例,设:z = a/(x-1)
则:-4 = a/(3-1)
a=-8
即:z=-8/(x-1)
y+1= 8/z =8/[-8/(x-1)] =-x+1
y=-x