1.[12-6y+( )]-[-5y^2-( )+( )]=2y^2+3y-4
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:数学作业 时间:2024/07/18 23:06:36
1.[12-6y+( )]-[-5y^2-( )+( )]=2y^2+3y-4
2.已知x^2-xy=8,xy-y^2=3.则x^2-y=( ),x^2-y^2=( )
a^3+a-4-( )=a^3-a^2+a
2.已知x^2-xy=8,xy-y^2=3.则x^2-y=( ),x^2-y^2=( )
a^3+a-4-( )=a^3-a^2+a
![1.[12-6y+( )]-[-5y^2-( )+( )]=2y^2+3y-4](/uploads/image/z/16704351-63-1.jpg?t=1.%5B12-6y%2B%28+%29%5D-%5B-5y%5E2-%28+%29%2B%28+%29%5D%3D2y%5E2%2B3y-4)
我直接填上了啊!
(1)[12-6y+(-3y^2)]-[-5y^2-(9y)+(16)]=2y^2+3y-4
(2)x^2-y^2=11
总的说,第1题答案是-3y^2 9y 16
第2题是11
(1)[12-6y+(-3y^2)]-[-5y^2-(9y)+(16)]=2y^2+3y-4
(2)x^2-y^2=11
总的说,第1题答案是-3y^2 9y 16
第2题是11
1.5y+8y-6y=2y-3
解3y+5/3y-6=1/2+5y-4/2y-4
4x-2y-6y*-y-3x+5y* *=2 就是平方
解方程:(y+4)/5+y+6=(y+8)/2-(y+4)/3
先化简,在求值:6y-(y+2分之y + 2-y分之y)除以y³-4y-2y²+8分之y,其中y=
(2y-3)(-y+4)=(y-2)(y-5)-3y(y-7/3)解方程
解方程 2y+5/3y-6-y/2=5y-4/2y-4
解方程:2y+5/3y-6 — y/2 = 5y-4/2y-4
解分式方程6y+12/y^2+4y+4 -y^2-4/y^2-4y+4 +y^2/y^2-4=0
1.((y+2x)(-2x+y)+4(x+2y)^2)/3y 2.(2(x-y)^3-8(x-y)^2(x+y)+6y(
解方程组:x+y/2+x-y/3=6 4(x+y)-5(x-y)=12
(-y+5+4y^2)-(-y^2+5y-4),其中y=-2