(x²+2x)²-7(x²+2x)-8 因式分解
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(x²+2x)²-7(x²+2x)-8 因式分解
![(x²+2x)²-7(x²+2x)-8 因式分解](/uploads/image/z/16654604-68-4.jpg?t=%EF%BC%88x%26%23178%3B%2B2x%29%26%23178%3B-7%EF%BC%88x%26%23178%3B%2B2x%29-8+%E5%9B%A0%E5%BC%8F%E5%88%86%E8%A7%A3)
( x" + 2x )" - 7( x" + 2x ) - 8
= ( x" + 2x )" + ( x" + 2x ) - 8( x" + 2x ) - 8
= ( x" + 2x + 1 )( x" + 2x ) - 8( x" + 2x + 1 )
= ( x + 1 )"( x" + 2x - 8 ) 再答: = ( x + 1 )”[ x” + 2x + 1 - 9 ]
= ( x + 1 )”[ ( x + 1 )” - 3” ]
= ( x + 1 )”( x + 1 - 3 )( x + 1 + 3 )
= ( x + 1 )”( x - 2 )( x + 4 )
再答: 原先就是没做完整,
留着做作业开动脑筋,
今天看到又有人赞同,
题目我就重新做一遍吧
再答: ( x” + 2x )” - 7( x” + 2x ) - 8
= ( x” + 2x )” + ( x” + 2x )
- 8( x” + 2x ) - 8
= ( x” + 2x )( x” + 2x + 1 )
- 8( x” + 2x + 1 )
= ( x” + 2x - 8 )( x” + 2x + 1 )
= [ x” + 4x - 2x - 8 ]( x + 1 )”
= [ x( x + 4 ) - 2( x + 4 ) ]( x + 1 )”
= ( x - 2 )( x + 4 )( x + 1 )”
= ( x" + 2x )" + ( x" + 2x ) - 8( x" + 2x ) - 8
= ( x" + 2x + 1 )( x" + 2x ) - 8( x" + 2x + 1 )
= ( x + 1 )"( x" + 2x - 8 ) 再答: = ( x + 1 )”[ x” + 2x + 1 - 9 ]
= ( x + 1 )”[ ( x + 1 )” - 3” ]
= ( x + 1 )”( x + 1 - 3 )( x + 1 + 3 )
= ( x + 1 )”( x - 2 )( x + 4 )
再答: 原先就是没做完整,
留着做作业开动脑筋,
今天看到又有人赞同,
题目我就重新做一遍吧
再答: ( x” + 2x )” - 7( x” + 2x ) - 8
= ( x” + 2x )” + ( x” + 2x )
- 8( x” + 2x ) - 8
= ( x” + 2x )( x” + 2x + 1 )
- 8( x” + 2x + 1 )
= ( x” + 2x - 8 )( x” + 2x + 1 )
= [ x” + 4x - 2x - 8 ]( x + 1 )”
= [ x( x + 4 ) - 2( x + 4 ) ]( x + 1 )”
= ( x - 2 )( x + 4 )( x + 1 )”