设随机事件A、B满足P(A)=0.4 P(B|A)=0.3,P(A|B)=0.6 则(A ∪ B)=
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设随机事件A、B满足P(A)=0.4 P(B|A)=0.3,P(A|B)=0.6 则(A ∪ B)=
![设随机事件A、B满足P(A)=0.4 P(B|A)=0.3,P(A|B)=0.6 则(A ∪ B)=](/uploads/image/z/16638606-54-6.jpg?t=%E8%AE%BE%E9%9A%8F%E6%9C%BA%E4%BA%8B%E4%BB%B6A%E3%80%81B%E6%BB%A1%E8%B6%B3P%28A%29%3D0.4+P%28B%7CA%29%3D0.3%2CP%28A%7CB%29%3D0.6+%E5%88%99%28A+%E2%88%AA+B%29%3D)
P(AB)=P(B|A)P(A)=0.3×0.4=0.12
P(B)=P(AB)/P(A|B)=0.12/0.6=0.2
P(A ∪ B)=P(A)+P(B)-P(AB)=0.4+0.2-0.12=0.48
P(B)=P(AB)/P(A|B)=0.12/0.6=0.2
P(A ∪ B)=P(A)+P(B)-P(AB)=0.4+0.2-0.12=0.48
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