实数x,y满足x2+y2+2x-4y+1=0求(1)y/(x-4)的最值(2)√(x2+y2-2x+1)的最值
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实数x,y满足x2+y2+2x-4y+1=0求(1)y/(x-4)的最值(2)√(x2+y2-2x+1)的最值
![实数x,y满足x2+y2+2x-4y+1=0求(1)y/(x-4)的最值(2)√(x2+y2-2x+1)的最值](/uploads/image/z/16619780-20-0.jpg?t=%E5%AE%9E%E6%95%B0x%2Cy%E6%BB%A1%E8%B6%B3x2%2By2%2B2x-4y%2B1%3D0%E6%B1%82%EF%BC%881%EF%BC%89y%EF%BC%8F%EF%BC%88x-4%EF%BC%89%E7%9A%84%E6%9C%80%E5%80%BC%EF%BC%882%EF%BC%89%E2%88%9A%EF%BC%88x2%2By2-2x%2B1%EF%BC%89%E7%9A%84%E6%9C%80%E5%80%BC)
x^2+Y^2+2X-4Y+1=0
X^2+2X+Y^2-4Y+1=0
X^2+2X-3+(Y-2)^2=0
(X+3)*(X-1)+(Y-2)^2=0
X=-3 Y=2或x=1 y=2
.
X^2+2X+Y^2-4Y+1=0
X^2+2X-3+(Y-2)^2=0
(X+3)*(X-1)+(Y-2)^2=0
X=-3 Y=2或x=1 y=2
.
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