求lim(n->无穷)(3n+5)/(n^2+n+4)^1/2的极限
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求lim(n->无穷)(3n+5)/(n^2+n+4)^1/2的极限
![求lim(n->无穷)(3n+5)/(n^2+n+4)^1/2的极限](/uploads/image/z/16551260-44-0.jpg?t=%E6%B1%82lim%28n-%3E%E6%97%A0%E7%A9%B7%29%283n%2B5%29%2F%28n%5E2%2Bn%2B4%29%5E1%2F2%E7%9A%84%E6%9E%81%E9%99%90)
lim(n->无穷)(3n+5)/(n^2+n+4)^1/2=lim(n->无穷) (3n+5)/[ n(1+1/n+4/n^2)^(1/2)
= lim(n->无穷) (3+5/n)/(1+1/n+4/n^2)^(1/2)
= 3.
= lim(n->无穷) (3+5/n)/(1+1/n+4/n^2)^(1/2)
= 3.
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