1.化简:sin80°(1+√3tan10°)
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:数学作业 时间:2024/07/28 13:34:34
1.化简:sin80°(1+√3tan10°)
2.若tan(α+π/4)=-3/5,则tan(α-π/4)=?
2.若tan(α+π/4)=-3/5,则tan(α-π/4)=?
![1.化简:sin80°(1+√3tan10°)](/uploads/image/z/16473504-48-4.jpg?t=1.%E5%8C%96%E7%AE%80%EF%BC%9Asin80%C2%B0%281%2B%E2%88%9A3tan10%C2%B0%29)
(1)sin80°(1+√3tan10°)
=cos10°(1+√3sin10°/cos10°)
=cos10°[(cos10°+√3sin10°)/cos10°]
=2(1/2cos10°+√3/2sin10°)
=2(sin30°cos10°+cos30°sin10°)
=2sin40°
本题原题怀疑是sin50°而不是sin80°
若是sin50°则答案是1
sin50°(1+√3tan10°)
=sin50°(1+√3sin10°/cos10°)
=sin50°[(cos10°+√3sin10°)/cos10°]
=2sin50°(1/2cos10°+√3/2sin10°)/cos10°
=2sin50°(sin30°cos10°+cos30°sin10°)/cos10°
=2sin50°sin40°/cos10°
=2cos40°sin40°/cos10°
=sin80°/cos10°
=cos10°/cos10°
=1
(2)tan(α-π/4)
=tan[π/2-(α+π/4)]
=sin[π/2-(α+π/4)]/cos[π/2-(α+π/4)]
=cos(α+π/4)/sin(α+π/4)
=1/tan(α+π/4)
=-5/3
=cos10°(1+√3sin10°/cos10°)
=cos10°[(cos10°+√3sin10°)/cos10°]
=2(1/2cos10°+√3/2sin10°)
=2(sin30°cos10°+cos30°sin10°)
=2sin40°
本题原题怀疑是sin50°而不是sin80°
若是sin50°则答案是1
sin50°(1+√3tan10°)
=sin50°(1+√3sin10°/cos10°)
=sin50°[(cos10°+√3sin10°)/cos10°]
=2sin50°(1/2cos10°+√3/2sin10°)/cos10°
=2sin50°(sin30°cos10°+cos30°sin10°)/cos10°
=2sin50°sin40°/cos10°
=2cos40°sin40°/cos10°
=sin80°/cos10°
=cos10°/cos10°
=1
(2)tan(α-π/4)
=tan[π/2-(α+π/4)]
=sin[π/2-(α+π/4)]/cos[π/2-(α+π/4)]
=cos(α+π/4)/sin(α+π/4)
=1/tan(α+π/4)
=-5/3
化简【2sin50°+sin80°(1+√3tan10°)】/cos5°
求值[2sin50°+sin10°(1+√3tan10°)]*√2(sin80°)*(sin80°)
[2sin50°+sin10°(1+√3tan10°)]*√2(sin80°)*(sin80度)
求值:[2sin50°+sin10°(1+√3tan10°)]×√2sin80°
求值:[2sin50°+sin80°(1+√3tan10°)]/√2cos5°
求[2sin50°+sin10°(1+√3tan10°0]sin80°的值
化简【2sin50°+sin10°(1+根号3tan10°)】乘根号下2(sin80°的平方)
求值:2sin50°+sin80°(1+3tan10°)1+cos10°
化简[2sin50°+sin10°(1+根号三tan10°)]*根号[2(sin80°)平方]拜托了各位
请问这个题怎么解?sin50°+sin10°(1+根号3*tan10°)根号下2*sin80°平方
1/sin10°-√3/sin80°
[2sin50+sin10(1+根号3tan10)]sin80