化简(sina+cosa)^2+2cos^2a
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:数学作业 时间:2024/08/03 15:37:05
化简(sina+cosa)^2+2cos^2a
![化简(sina+cosa)^2+2cos^2a](/uploads/image/z/16406565-69-5.jpg?t=%E5%8C%96%E7%AE%80%28sina%2Bcosa%29%5E2%2B2cos%5E2a)
原式=sin²a+cos²a+2sinacosa+2cos²a
=1+sin2a+2(1+cos2a)/2
=sin2a+cos2a+2
=√2sin(2a+π/4)+2
=1+sin2a+2(1+cos2a)/2
=sin2a+cos2a+2
=√2sin(2a+π/4)+2
证明(1-cos^2a)/(sina+cosa)-(sina+cosa)/(tan^2a-1)=sina+cosa
证明(1-cos^2a)/(sina-cosa)-(sina+cosa)/(tan^2-1)=sina+cosa
Sin^4a+Sina*Cosa+Cos^2a化简
已知sin a+cos a=1/2 sina*cosa=?cos a/sina+sina/cosa=?
化简(1+sina+cosa)[sin(a/2)-cos(a/2)]/根号(2+2cosa) (0°
求证:1-cos^2a/sina-cosa - sina+cosa/tan^2a-1=sina+cosa
已知tana=3,求(3sina-2cosa)/(2sina+5cosa) ; cos^2a ; sina*cosa
1.化简3(sina+cosa)^4+6(sina-cosa)^2+4(sin^6a+cos^6a)
已知tana=3,求①sina+cosa/2sina-cosa ②sin²a+sina·cosa+3cos
cos^2a-sin^2a=(cosa+sina)(cosa-sina)吗?
若tanA=2,则(sinA+cosA)/(sinA-cosA)+cos^2(A)
若tana=2 则(sina+cosa)/(sina-cosa)+cos^2a=