2道二次根式(3根号2+根号3-根号5)^2-(3根号2-根号3+根号5)^2 (1+根号2)^2(1+根号3)^2(1
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2道二次根式
(3根号2+根号3-根号5)^2-(3根号2-根号3+根号5)^2 (1+根号2)^2(1+根号3)^2(1-根号2)^2(1-根号3)^2
(3根号2+根号3-根号5)^2-(3根号2-根号3+根号5)^2 (1+根号2)^2(1+根号3)^2(1-根号2)^2(1-根号3)^2
![2道二次根式(3根号2+根号3-根号5)^2-(3根号2-根号3+根号5)^2 (1+根号2)^2(1+根号3)^2(1](/uploads/image/z/16403652-36-2.jpg?t=2%E9%81%93%E4%BA%8C%E6%AC%A1%E6%A0%B9%E5%BC%8F%EF%BC%883%E6%A0%B9%E5%8F%B72%2B%E6%A0%B9%E5%8F%B73-%E6%A0%B9%E5%8F%B75%EF%BC%89%5E2-%283%E6%A0%B9%E5%8F%B72-%E6%A0%B9%E5%8F%B73%2B%E6%A0%B9%E5%8F%B75%EF%BC%89%5E2+%EF%BC%881%2B%E6%A0%B9%E5%8F%B72%EF%BC%89%5E2%281%2B%E6%A0%B9%E5%8F%B73%EF%BC%89%5E2%281)
(3√2+√3-√5)^2-(3√2-√3+√5)^2
=[(3√2+√3-√5)-(3√2-√3+√5)][(3√2+√3-√5)+(3√2-√3+√5)]
=(3√2+√3-√5-3√2+√3-√5)(3√2+√3-√5+3√2-√3+√5)
=(2√3-2√5)*6√2
=2(√3-√5)*6√2
=12(√3-√5)*√2
=12√6-12√10
(1+√2)^2(1+√3)^2(1-√2)^2(1-√3)^2
=(1+√2)^2(1-√2)^2(1-√3)^2(1+√3)^2
=[(1+√2)^2(1-√2)^2][(1-√3)^2(1+√3)^2]
=[(1+√2)(1-√2)]^2[(1-√3)(1+√3)]^2
=[1-2]^2*[1-3]^2
=1*4
=4
=[(3√2+√3-√5)-(3√2-√3+√5)][(3√2+√3-√5)+(3√2-√3+√5)]
=(3√2+√3-√5-3√2+√3-√5)(3√2+√3-√5+3√2-√3+√5)
=(2√3-2√5)*6√2
=2(√3-√5)*6√2
=12(√3-√5)*√2
=12√6-12√10
(1+√2)^2(1+√3)^2(1-√2)^2(1-√3)^2
=(1+√2)^2(1-√2)^2(1-√3)^2(1+√3)^2
=[(1+√2)^2(1-√2)^2][(1-√3)^2(1+√3)^2]
=[(1+√2)(1-√2)]^2[(1-√3)(1+√3)]^2
=[1-2]^2*[1-3]^2
=1*4
=4
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