(a^m+1b^n+2)(a^2n-1b^2n)=a^5b^5,求m+n的值
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(a^m+1b^n+2)(a^2n-1b^2n)=a^5b^5,求m+n的值
![(a^m+1b^n+2)(a^2n-1b^2n)=a^5b^5,求m+n的值](/uploads/image/z/16323954-42-4.jpg?t=%28a%5Em%2B1b%5En%2B2%29%28a%5E2n-1b%5E2n%29%3Da%5E5b%5E5%2C%E6%B1%82m%2Bn%E7%9A%84%E5%80%BC)
(a^m+1b^n+2)(a^2n-1b^2n)=a^5b^5?
[a^(m+1)b^(n+2)][(^(2n-1)b^(2n)]=a^5b^5
=a^(m+2n)b^(3n+2)
3n+2=5,n=1
m+2n=5,m=3
m+n=4
[a^(m+1)b^(n+2)][(^(2n-1)b^(2n)]=a^5b^5
=a^(m+2n)b^(3n+2)
3n+2=5,n=1
m+2n=5,m=3
m+n=4
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